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    <div class="s4s-environment-example" id="EXAMPLE.3b7c26b7-aa30-484c-bcb7-f70e428619ab">
      <p class="s4s-noindent">
        <span class="s4s-environment-example-tag">Пример 2. </span>Намерете следните видове уравнения на правата  p, определена от точките <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>A</mi><mo>=</mo><mrow><mo>(</mo><mn>3,</mn><mspace width="mediummathspace" height="0.2em"/><mn>6</mn><mo>)</mo></mrow><mn>,</mn><mspace width="2mm" height="2mm"/><mi>B</mi><mo>=</mo><mrow><mo>(</mo><mo>−</mo><mn>2,</mn><mspace width="mediummathspace" height="0.2em"/><mn>1</mn><mo>)</mo></mrow></math></p>
      <p>а) декартово уравнение на права</p>
      <p>б) общо уравнение на права</p>
      <p>в) с точка и направляващ вектор</p>
      <p>г) параметрично уравнение</p>
      <p>д) векторно уравнение</p>
    </div>
    <div class="s4s-environment-solution" id="SOLUTION.35a9350f-798e-49d7-93dc-48f392232f45">
      <p class="s4s-noindent">
          <span class="s4s-environment-solution-tag">Решение 2. </span>а) Наклонът на правата p=AB е:   <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>m</mi><mo>=</mo><mfrac><mrow><mn>1</mn><mo>−</mo><mn>6</mn></mrow><mrow><mo>−</mo><mn>2</mn><mo>−</mo><mn>3</mn></mrow></mfrac><mo>=</mo><mfrac><mrow><mo>−</mo><mn>5</mn></mrow><mrow><mo>−</mo><mn>5</mn></mrow></mfrac><mo>=</mo><mn>1</mn></math></p>
      <p>и можем да запишем уравнението на правата във вида  </p>
      <table width="95%" class="s4s-eq">
        <tbody>
          <tr>
            <td align="center">
              <math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
                <mi>y</mi>
                <mo>−</mo>
                <mi>b</mi>
                <mo>=</mo>
                <mi>m</mi>
                <mrow>
                  <mo>(</mo>
                  <mi>x</mi>
                  <mo>−</mo>
                  <mn>0</mn>
                  <mo>)</mo>
                  <mspace width="mediummathspace" height="0.2em"/>
                  <mo>⇒</mo>
                  <mi>y</mi>
                  <mo>−</mo>
                  <mi>b</mi>
                  <mo>=</mo>
                  <mi>x</mi>
                </mrow>
              </math>
            </td>
          </tr>
        </tbody>
      </table>
      <p class="s4s-noindent">Координатите точките  A  и  B  на правата удовлетворчват уравнението, следователно, </p>
      <table width="95%" class="s4s-eq">
        <tbody>
          <tr>
            <td align="center">
              <math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
                <mn>6</mn>
                <mo>−</mo>
                <mi>b</mi>
                <mo>=</mo>
                <mn>3</mn>
                <mo>,</mo>
                <mrow>
                  <mspace width="mediummathspace" height="0.2em"/>
                  <mi mathvariant="italic">or</mi>
                  <mspace width="mediummathspace" height="0.2em"/>
                  <mn>1</mn>
                  <mo>−</mo>
                  <mi>b</mi>
                  <mo>=</mo>
                  <mo>−</mo>
                  <mn>2</mn>
                </mrow>
              </math>
            </td>
          </tr>
        </tbody>
      </table>
      <table width="95%" class="s4s-eq">
        <tbody>
          <tr>
            <td align="center">
              <math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
                <mi>b</mi>
                <mo>=</mo>
                <mn>3</mn>
              </math>
            </td>
          </tr>
        </tbody>
      </table>
      <p class="s4s-noindent"> Декартовото уравнение на правата е: </p>
      <table width="95%" class="s4s-eq">
        <tbody>
          <tr>
            <td align="center">
              <math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
                <mi>y</mi>
                <mo>=</mo>
                <mi>x</mi>
                <mo>+</mo>
                <mn>3</mn>
              </math>
            </td>
          </tr>
        </tbody>
      </table>
      <p class="s4s-noindent">б) Общото уравнение на права има вида</p>
      <table width="95%" class="s4s-eq">
        <tbody>
          <tr>
            <td align="center">
              <math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
                <mi>A</mi>
                <mi>x</mi>
                <mo>+</mo>
                <mi>B</mi>
                <mi>y</mi>
                <mo>+</mo>
                <mi>C</mi>
                <mo>=</mo>
                <mn>0,</mn>
              </math>
            </td>
          </tr>
        </tbody>
      </table>
      <p class="s4s-noindent"> който лесно може да се получи от уравнение а) като </p>
      <table width="95%" class="s4s-eq">
        <tbody>
          <tr>
            <td align="center">
              <math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
                <mi>x</mi>
                <mo>−</mo>
                <mi>y</mi>
                <mo>+</mo>
                <mn>3</mn>
                <mo>=</mo>
                <mn>0</mn>
              </math>
            </td>
          </tr>
        </tbody>
      </table>
      <p class="s4s-noindent">в) Точките  A  и  B определят насочената отсечка <math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="bold-italic">a</mi><mo>=</mo><mover><mrow><mi>A</mi><mi>B</mi></mrow><mo>→</mo></mover><mo>=</mo><mi>B</mi><mo>−</mo><mi>A</mi><mo>=</mo><mrow><mo>(</mo><mo>−</mo><mn>5</mn><mo>,</mo><mo>−</mo><mn>5</mn><mo>)</mo></mrow></math>, която е представител на колинеарния на правата вектор и търсеното уравнение става </p>
      <table width="95%" class="s4s-eq">
        <tbody>
          <tr>
            <td align="center">
              <math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
                <mi>X</mi>
                <mo>=</mo>
                <mi>A</mi>
                <mo>+</mo>
                <mi>t</mi>
                <mspace width="mediummathspace" height="0.2em"/>
                <mi mathvariant="bold-italic">a</mi>
                <mo>,</mo>
                <mspace width="mediummathspace" height="0.2em"/>
                <mi>t</mi>
                <mo>∈</mo>
                <mrow>
                  <mi>R</mi>
                </mrow>
              </math>
            </td>
          </tr>
        </tbody>
      </table>
      <table width="95%" class="s4s-eq">
        <tbody>
          <tr>
            <td align="center">
              <math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
                <mi>X</mi>
                <mo>=</mo>
                <mrow>
                  <mo>(</mo>
                  <mn>3</mn>
                  <mo>,</mo>
                  <mspace width="mediummathspace" height="0.2em"/>
                  <mn>6</mn>
                  <mo>)</mo>
                </mrow>
                <mo>+</mo>
                <mi>t</mi>
                <mspace width="mediummathspace" height="0.2em"/>
                <mrow>
                  <mo>(</mo>
                  <mo>−</mo>
                  <mn>5</mn>
                  <mo>,</mo>
                  <mo>−</mo>
                  <mn>5</mn>
                  <mo>)</mo>
                </mrow>
                <mrow>
                  <mo>,</mo>
                  <mspace width="mediummathspace" height="0.2em"/>
                  <mi>t</mi>
                  <mo>∈</mo>
                  <mi>R</mi>
                </mrow>
              </math>
            </td>
          </tr>
        </tbody>
      </table>
      <p class="s4s-noindent">г) Следното дава параметричната форма на уравненията на правата за   <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>t</mi><mo>∈</mo><mi>R</mi></math></p>
      <table width="95%" class="s4s-eq">
        <tbody>
          <tr>
            <td align="center">
              <math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
                <mi>x</mi>
                <mo>=</mo>
                <mn>3</mn>
                <mo>−</mo>
                <mn>5</mn>
                <mi>t</mi>
              </math>
            </td>
          </tr>
        </tbody>
      </table>
      <table width="95%" class="s4s-eq">
        <tbody>
          <tr>
            <td align="center">
              <math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
                <mi>y</mi>
                <mo>=</mo>
                <mn>6</mn>
                <mo>−</mo>
                <mn>5</mn>
                <mi>t</mi>
              </math>
            </td>
          </tr>
        </tbody>
      </table>
      <p class="s4s-noindent">д) Векторното уравнение на правата се получава от в), като се запише във вида: </p>
      <table width="95%" class="s4s-eq">
        <tbody>
          <tr>
            <td align="center">
              <math xmlns="http://www.w3.org/1998/Math/MathML" display="block">
                <mi mathvariant="bold-italic">r</mi>
                <mrow>
                  <mo>(</mo>
                  <mi>t</mi>
                  <mo>)</mo>
                </mrow>
                <mo>=</mo>
                <mrow>
                  <mo>(</mo>
                  <mn>3</mn>
                  <mo>−</mo>
                  <mn>5</mn>
                  <mi>t</mi>
                  <mo>,</mo>
                  <mspace width="mediummathspace" height="0.2em"/>
                  <mn>6</mn>
                  <mo>−</mo>
                  <mn>5</mn>
                  <mi>t</mi>
                  <mo>)</mo>
                  <mo>,</mo>
                  <mspace width="mediummathspace" height="0.2em"/>
                  <mi>t</mi>
                  <mo>∈</mo>
                  <mi>R</mi>
                </mrow>
              </math>
            </td>
          </tr>
        </tbody>
      </table>
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